Support generics in generated `export!` macro in Rust

[tqwewe]

The wit_bindgen::generate! macro generates a export! macro which has the following syntax supported:

    ($ty:ident) => ...;
    ($ty:ident with_types_in $($path_to_types_root:tt)*) => ...;

Since $ty is an ident only, it means I'm unable to pass in a path or type with generics, which is quite limiting.

My use case is something like this:

#[macro_export]
macro_rules! export_projection {
    ($ty:path) => {
        $crate::runtime::projection::export!(
            $crate::runtime::projection::Projection<$ty> with_types_in $crate::runtime::projection
        );
    };
}
pub struct Projection<T>(PhantomData<T>);

pub struct ProjectionState<T> {
    inner: RefCell<T>,
}

impl<T: EventHandler + 'static> Guest for Projection<T> {
    type ProjectionState = ProjectionState<T>;
}

impl<T: EventHandler + 'static> GuestProjectionState for ProjectionState<T> {
    ...
}

But with the export! macro only accepting an ident, it becomes problematic.

I've experimented with simply changing wit_bindgen to use path instead of ident, which seems to work no problem. The only issue is with_types_in isn't supported here, so it needs to be changed to something like $ty => $path_to_types_root.

[alexcrichton]

It'd be a bit of a workaround, but one thing you can do is:

type T = Projection<TheType>;
export!(T);

(more-or-less within the macro)

[tqwewe]

Thats true. The only downside to this though is it makes a new type T which might conflict with a users existing type. This isn't a huge issue, especially if I did type __ProjectionExport = Projection<TheType>, but this is quite ugly, and would also likely be marked with #[docs(hidden)]

[alexcrichton]

Agreed yeah, still best to fix IMO