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Copy pathLongestConsecutiveSequence.py
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executable file
·53 lines (35 loc) · 1.13 KB
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"""
Given an unsorted array of integers nums, return the length of the longest consecutive elements sequence.
You must write an algorithm that runs in O(n) time.
Example 1:
Input: nums = [100,4,200,1,3,2]
Output: 4
Explanation: The longest consecutive elements sequence is [1, 2, 3, 4]. Therefore its length is 4.
Example 2:
Input: nums = [0,3,7,2,5,8,4,6,0,1]
Output: 9
Constraints:
0 <= nums.length <= 105
-109 <= nums[i] <= 109
"""
from typing import List
class Solution:
def longestConsecutive(self, nums: List[int]) -> int:
if not nums:
return 0
num_set = set(nums)
longest_streak = 0
for num in num_set:
if num - 1 not in num_set:
current_num = num
current_streak = 1
while current_num + 1 in num_set:
current_num += 1
current_streak += 1
longest_streak = max(longest_streak, current_streak)
return longest_streak
# Test case
solution = Solution()
nums = [100, 4, 200, 1, 3, 2]
result = solution.longestConsecutive(nums)
print(result) # Expected output: 4