In task we have
Давайте попробуем здесь сэкономить 1 бит:
We aren't actually saving 1 bit. From task implementation details it follows that we saving just 1/2 bit (because we still need allocation bit, but not for each block, only for pair of blocks.)
Seems like it's a bit of confused task description, probably it needs to be adjusted.
In task we have
We aren't actually saving 1 bit. From task implementation details it follows that we saving just 1/2 bit (because we still need allocation bit, but not for each block, only for pair of blocks.)
Seems like it's a bit of confused task description, probably it needs to be adjusted.