Merging the PR

02_activities/assignments/Cohort_8/assignment1.sql

@@ -5,16 +5,22 @@
 --SELECT
 /* 1. Write a query that returns everything in the customer table. */
 
+SELECT * FROM customer;
 
 
 /* 2. Write a query that displays all of the columns and 10 rows from the cus- tomer table, 
 sorted by customer_last_name, then customer_first_ name. */
 
+SELECT * FROM customer 
+ORDER BY customer_last_name, customer_first_name 
+LIMIT 10;
 
 
 --WHERE
 /* 1. Write a query that returns all customer purchases of product IDs 4 and 9. */
 
+SELECT * FROM customer_purchases 
+WHERE product_id IN (4, 9);
 
 
 /*2. Write a query that returns all customer purchases and a new calculated column 'price' (quantity * cost_to_customer_per_qty), 
@@ -26,28 +32,62 @@ filtered by customer IDs between 8 and 10 (inclusive) using either:
 
 
 -- option 2
+-- option 1 (using AND)
+SELECT *, ROUND((quantity * cost_to_customer_per_qty), 2) AS price 
+FROM customer_purchases 
+WHERE customer_id >= 8 AND customer_id <= 10;
 
+-- option 2 (using BETWEEN)
+SELECT *, ROUND((quantity * cost_to_customer_per_qty), 2) AS price 
+FROM customer_purchases 
+WHERE customer_id BETWEEN 8 AND 10;
 
 
 --CASE
-/* 1. Products can be sold by the individual unit or by bulk measures like lbs. or oz. 
-Using the product table, write a query that outputs the product_id and product_name
+/* @@ -35,35 +51,71 @@ Using the product table, write a query that outputs the product_id and product_n
 columns and add a column called prod_qty_type_condensed that displays the word “unit” 
 if the product_qty_type is “unit,” and otherwise displays the word “bulk.” */
-
+SELECT
+    product_id,
+    product_n,
+    CASE 
+        WHEN product_qty_type = 'unit' THEN 'unit'
+        ELSE 'bulk'
+    END AS prod_qty_type_condensed
+FROM product;
 
 
 /* 2. We want to flag all of the different types of pepper products that are sold at the market. 
 add a column to the previous query called pepper_flag that outputs a 1 if the product_name 
 contains the word “pepper” (regardless of capitalization), and otherwise outputs 0. */
 
+SELECT 
+	product_id, 
+	product_name,
+	CASE
+		WHEN product_qty_type = 'unit' 
+		THEN 'unit'
+		ELSE 'bulk'
+	END AS prod_qty_type_condensed,
+	CASE
+		WHEN product_name LIKE '%pepper%' 
+		THEN 1
+		ELSE 0
+	END AS pepper_flag
+FROM product;
 
 
 --JOIN
 /* 1. Write a query that INNER JOINs the vendor table to the vendor_booth_assignments table on the 
 vendor_id field they both have in common, and sorts the result by vendor_name, then market_date. */
 
 
+SELECT * FROM vendor AS v
+INNER JOIN vendor_booth_assignments AS vba
+	ON v.vendor_id = vba.vendor_id
+ORDER BY
+	v.vendor_name,
+	vba.market_date;
 
 
 /* SECTION 3 */
@@ -56,6 +96,11 @@ vendor_id field they both have in common, and sorts the result by vendor_name, t
 /* 1. Write a query that determines how many times each vendor has rented a booth 
 at the farmer’s market by counting the vendor booth assignments per vendor_id. */
 
+SELECT 
+	vendor_id, 
+	COUNT(vendor_id) AS number_booth_rentals
+FROM vendor_booth_assignments
+GROUP BY vendor_id;
 
 
 /* 2. The Farmer’s Market Customer Appreciation Committee wants to give a bumper 
@@ -64,20 +109,35 @@ of customers for them to give stickers to, sorted by last name, then first name.
 
 HINT: This query requires you to join two tables, use an aggregate function, and use the HAVING keyword. */
 
-
-
---Temp Table
-/* 1. Insert the original vendor table into a temp.new_vendor and then add a 10th vendor: 
-Thomass Superfood Store, a Fresh Focused store, owned by Thomas Rosenthal
-
-HINT: This is two total queries -- first create the table from the original, then insert the new 10th vendor. 
-When inserting the new vendor, you need to appropriately align the columns to be inserted 
-(there are five columns to be inserted, I've given you the details, but not the syntax) 
-
+SELECT
+	c.customer_id,
+	c.customer_first_name,
+	c.customer_last_name,
+	ROUND(SUM(cp.quantity * cp.cost_to_customer_per_qty), 2) AS total_spent
+FROM customer AS c
+JOIN customer_purchases AS cp
+	ON c.customer_id = cp.customer_id
+GROUP BY 
+	c.customer_id,
+	c.customer_first_name,
+	c.customer_last_name
+HAVING
+	total_spent > 2000.00
+ORDER BY
+	total_spent DESC,
+	c.customer_last_name ASC,
+	c.customer_first_name ASC;
+
+
+/* --Temp Table
+@@ -77,20 +129,11 @@ When inserting the new vendor, you need to appropriately align the columns to be
 -> To insert the new row use VALUES, specifying the value you want for each column:
 VALUES(col1,col2,col3,col4,col5) 
 */
+DROP TABLE IF EXISTS new_vendor;
 
+CREATE TEMPORARY TABLE new_vendor AS
+SELECT * FROM vendor;
 
 
 -- Date
@@ -93,4 +153,5 @@ Remember that money spent is quantity*cost_to_customer_per_qty.
 
 HINTS: you will need to AGGREGATE, GROUP BY, and filter...
 but remember, STRFTIME returns a STRING for your WHERE statement!! */
-
+INSERT INTO new_vendor (vendor_id, vendor_name, vendor_type, vendor_owner_first_name, vendor_owner_last_name)
+VALUES (10, 'Thomass Superfood Store', 'Fresh Focused', 'Thomas', 'Rosenthal');

02_activities/assignments/Cohort_8/assignment2.sql

@@ -33,18 +33,58 @@ You can either display all rows in the customer_purchases table, with the counte
 each new market date for each customer, or select only the unique market dates per customer 
 (without purchase details) and number those visits. 
 HINT: One of these approaches uses ROW_NUMBER() and one uses DENSE_RANK(). */
-
+Select customer_id,
+	   market_date,
+	   ROW_NUMBER() over (partition by customer_id order by market_date) as visit_number
+  from customer_purchases
+ order by customer_id, market_date;
+ Select distinct customer_id,
+	   market_date,
+	   DENSE_RANK() over (partition by customer_id order by market_date) as visit_number
+  from customer_purchases
+ order by customer_id, market_date;
 
 
 /* 2. Reverse the numbering of the query from a part so each customer’s most recent visit is labeled 1, 
 then write another query that uses this one as a subquery (or temp table) and filters the results to 
 only the customer’s most recent visit. */
 
+select customer_id,
+	   market_date,
+	   ROW_NUMBER() over (partition by customer_id order by market_date desc) as visit_number_reverse
+  from customer_purchases
+ order by customer_id, market_date desc;
+
+ --subquery
+ select *
+   from (select customer_id,
+	            market_date,
+	            ROW_NUMBER() over (partition by customer_id order by market_date desc) as visit_number_reverse
+	       from customer_purchases)
+  where visit_number_reverse = 1
+  order by customer_id;
+--or
+CREATE TEMPORARY TABLE temp_customer_visits AS
+SELECT 
+    customer_id,
+    market_date,
+    ROW_NUMBER() OVER (PARTITION BY customer_id ORDER BY market_date DESC) AS visit_number_reverse
+FROM customer_purchases;
+SELECT *
+FROM temp_customer_visits
+WHERE visit_number_reverse = 1
+ORDER BY customer_id;
+DROP TABLE temp_customer_visits;
 
 
 /* 3. Using a COUNT() window function, include a value along with each row of the 
 customer_purchases table that indicates how many different times that customer has purchased that product_id. */
-
+select customer_id,
+	   product_id,
+	   market_date,
+	   COUNT(product_id) over (partition by customer_id, product_id) as total_purchases_per_product
+  from customer_purchases
+ order by customer_id, product_id, market_date;
 
 
 -- String manipulations
@@ -58,11 +98,19 @@ Remove any trailing or leading whitespaces. Don't just use a case statement for
 | Habanero Peppers - Organic | Organic     |
 
 Hint: you might need to use INSTR(product_name,'-') to find the hyphens. INSTR will help split the column. */
-
+SELECT 
+    product_name,
+    CASE 
+        WHEN INSTR(product_name,'-') > 0 THEN TRIM(SUBSTR(product_name, INSTR(product_name,'-') + 1))
+        ELSE NULL
+    END AS description
+FROM product;
 
 
 /* 2. Filter the query to show any product_size value that contain a number with REGEXP. */
-
+select *
+  from product
+ where product_size REGEXP '[0-9]';
 
 
 -- UNION
@@ -74,8 +122,31 @@ HINT: There are a possibly a few ways to do this query, but if you're struggling
 "best day" and "worst day"; 
 3) Query the second temp table twice, once for the best day, once for the worst day, 
 with a UNION binding them. */
-
-
+WITH sales_per_day AS (
+    SELECT 
+        market_date,
+        SUM(quantity * cost_to_customer_per_qty) AS total_sales
+    FROM customer_purchases
+    GROUP BY market_date
+),
+ranked_sales AS (
+    SELECT 
+        market_date,
+        total_sales,
+        RANK() OVER (ORDER BY total_sales DESC) AS rank_desc,
+        RANK() OVER (ORDER BY total_sales ASC) AS rank_asc
+    FROM sales_per_day
+)
+SELECT 'Best Day' AS sale_type, market_date, total_sales
+FROM ranked_sales
+WHERE rank_desc = 1
+
+UNION
+
+SELECT 'Worst Day' AS sale_type, market_date, total_sales
+FROM ranked_sales
+WHERE rank_asc = 1
+ORDER BY sale_type DESC;  
 
 
 /* SECTION 3 */
@@ -90,6 +161,27 @@ Remember, CROSS JOIN will explode your table rows, so CROSS JOIN should likely b
 Think a bit about the row counts: how many distinct vendors, product names are there (x)?
 How many customers are there (y). 
 Before your final group by you should have the product of those two queries (x*y).  */
+WITH vendor_products AS (
+    SELECT DISTINCT vi.vendor_id, vi.product_id, vi.original_price
+    FROM vendor_inventory vi
+),
+
+
+customer_count AS (
+    SELECT COUNT(DISTINCT customer_id) AS total_customers
+    FROM customer
+)
+
+
+SELECT 
+    v.vendor_name,
+    p.product_name,
+    vp.original_price * 5 * cc.total_customers AS total_revenue
+FROM vendor_products vp
+JOIN vendor v ON vp.vendor_id = v.vendor_id
+JOIN product p ON vp.product_id = p.product_id
+CROSS JOIN customer_count cc
+ORDER BY v.vendor_name, p.product_name;
 
 
 
@@ -98,20 +190,27 @@ Before your final group by you should have the product of those two queries (x*y
 This table will contain only products where the `product_qty_type = 'unit'`. 
 It should use all of the columns from the product table, as well as a new column for the `CURRENT_TIMESTAMP`.  
 Name the timestamp column `snapshot_timestamp`. */
-
+Create Table product_units as
+Select *,
+	   CURRENT_TIMESTAMP as snapshot_timestamp
+ from product
+ where product_qty_type ='unit';
+select * from product_units;
 
 
 /*2. Using `INSERT`, add a new row to the product_units table (with an updated timestamp). 
 This can be any product you desire (e.g. add another record for Apple Pie). */
-
-
+Insert into product_units (product_id, product_name, product_size, product_qty_type, snapshot_timestamp)
+VALUES (11, 'Apple Pie', '1 unit', 'unit', CURRENT_TIMESTAMP);	
+select * from product_units;
 
 -- DELETE
 /* 1. Delete the older record for the whatever product you added. 
 
-HINT: If you don't specify a WHERE clause, you are going to have a bad time.*/
-
-
+HINT: If you don't specify a WHERE clause, you are going to have a bad time.*/ 
+Delete from product_units
+ where product_id =11
+   and snapshot_timestamp < (select max(snapshot_timestamp) from product_units where product_id =11);
 
 -- UPDATE
 /* 1.We want to add the current_quantity to the product_units table. 
@@ -129,6 +228,24 @@ Third, SET current_quantity = (...your select statement...), remembering that WH
 Finally, make sure you have a WHERE statement to update the right row, 
 	you'll need to use product_units.product_id to refer to the correct row within the product_units table. 
 When you have all of these components, you can run the update statement. */
+Alter Table product_units
+ADD current_quantity INT;
+UPDATE product_units pu
+SET current_quantity = (
+    SELECT COALESCE(vi.quantity, 0)
+    FROM vendor_inventory vi
+    JOIN (
+        SELECT product_id, MAX(vendor_inventory_id) AS last_id
+        FROM vendor_inventory
+        GROUP BY product_id
+    ) last_vi
+    ON vi.product_id = last_vi.product_id
+    AND vi.vendor_inventory_id = last_vi.last_id
+    WHERE vi.product_id = pu.product_id
+);
+
+select * from product_units;
+
 
 
 

farmersmarket - Assignment 1 Section 2.sqbpro

@@ -0,0 +1 @@
+<?xml version="1.0" encoding="UTF-8"?><sqlb_project><db path="C:/Users/admin/sql/05_src/sql/farmersmarket.db" readonly="0" foreign_keys="1" case_sensitive_like="0" temp_store="0" wal_autocheckpoint="1000" synchronous="2"/><attached/><window><main_tabs open="structure browser pragmas query" current="3"/></window><tab_structure><column_width id="0" width="300"/><column_width id="1" width="0"/><column_width id="2" width="100"/><column_width id="3" width="8651"/><column_width id="4" width="0"/><expanded_item id="0" parent="1"/><expanded_item id="1" parent="1"/><expanded_item id="2" parent="1"/><expanded_item id="3" parent="1"/><expanded_item id="4" parent="1"/></tab_structure><tab_browse><table title="booth" custom_title="0" dock_id="1" table="4,5:mainbooth"/><dock_state state="000000ff00000000fd00000001000000020000000000000000fc0100000001fb000000160064006f0063006b00420072006f00770073006500310100000000ffffffff0000011800ffffff000000000000000000000004000000040000000800000008fc00000000"/><default_encoding codec=""/><browse_table_settings/></tab_browse><tab_sql><sql name="assignment1.sql" filename="C:/Users/admin/sql/02_activities/assignments/Cohort_8/assignment1.sql">-- Reference to file &quot;C:/Users/admin/sql/02_activities/assignments/Cohort_8/assignment1.sql&quot; (not supported by this version) --</sql><current_tab id="0"/></tab_sql></sqlb_project>