Fix undefined behaviour in number serialisation.#36
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When optimising, the compiler is allowed to reorder the read calls
in the following code:
return (uint16_t)read_uint8_t(info) |
((uint16_t)read_uint8_t(info) << 8);
Since read_uint8_t() has side effects, this could read a totally
wrong value and has to be rewritten as such:
uint16_t value = (uint16_t)read_uint8_t(info);
value |= (uint16_t)read_uint8_t(info) << 8;
return value;
This bug has been observed with Visual Studio 2019.
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When optimising, the compiler is allowed to reorder the read calls
in the following code:
Since read_uint8_t() has side effects, this could read a totally
wrong value and has to be rewritten as such:
This bug has been observed with Visual Studio 2019.